Time & Work Questions
Question
A group of men decided to do a work in 10 days but 5 of them remained absent. If the rest of the group finished the work in 12 days; find the original number of men?
Solution
Let us assume x Mens are working there initially.
so x men completes the job in 10 days. i.e. x --> 1/10 part of work per day.
similarly if 5 of them were absent means they will finish it at 12 days.
i.e. (x-5)=1/12
Here one man work will be same for the both condition, therefore
1/10x = 1/12(x-5)
10x=12(x-5)
2x=60 ==> x=30.
therefore total number of men at the begining is 30.
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