Problems on Ages Questions
Radhika has two daughters by name Rinku and Sindhu. The ratio of the age of Radhika and Rinku is 3:1 and that of Rinku and Sindhu is 8:5. Given that Rinku is six years elder to Sindhu. Find the ratio of their ages after 12 years.
Solution
Ans.D
The ratio of the ages of Radhika and Rinku is 3:1.
Let their ages be 3x and x respectively –(1).
The ratio of ages of Rinku and Sindhu is 8:5.
Let their ages be 8y and 5y.
Given that Rinku is 6 years elder to Sindhu. 8y - 5y =
6 ⇒ y = 2.
Thus,the present ages of Rinku and Sindhu are 8 × 2 =
16 and 5 × 2 = 10 respectively.—(2)
From (1) and (2),we have x = 16.
Therefore,the age of Radhika is 3 × 16 = 48.
After 12 years,their ages would be 48 + 12 = 60,16 + 12
= 28 and 10 + 12 = 22 respectively.
So,the ratio is 60 : 28 : 22 or 30 : 14 : 11 (dividing
throughout by 2).
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